Factor. 8x^5 + 4x^2 − 12 A. 8 (x^5 + 4x^2 − 12) B. 4 (2x^5 + x^2−3) C. 4x^2 (2x^3 + x − 3) D. 4 (2x^5 + 4x^2 − 12)
is there a common factor?
NO
Yes there is, what number goes evenly into 8, 4, and -12?
4
@moreso
can you finish the problem now?
the answer is C
incorrect
oh it's C or A so it's either B or D so it's B
@moreso
its b just factor the equation
it's B cause i figured
oh please.. you know u didnt lol
what ? lol
do you an explanation how i did it or you got it? :3
i had an explanation until i deleted by accident before you logged in
but baby you're smart
aye kid welp this how you do it we pickd b which was 4( 2x^5+x^2- 3) if you distribute the 4 you will get the same answer from your original equation which we will get 8 x^5 + 4x^2- 12.. distribution means that you are multiplying the 4 to (2x^5) then 4(x^2) then (4)(-3)
correct 100% correct and then combine the terms
but i really appreciate it, thank you so very much
yw
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