Question

solve the diff eq

Answer 1

\[y'=sinx(ysec x - 2)\]

Answer 2

@Zepdrix

Answer 3

i got stuck .. not sure if im doing it good

Answer 4

Mmmm ya looks good so far.

Answer 5

oh got it ;p

Answer 6

\[\large\rm (\cos x)y=-2\int\limits \sin x \cos x~dx\]

Answer 7

Figure out the rest? :d

Answer 8

would that be a trig identity?

Answer 9

i got \[y= \frac{ 1 }{ cosx }(\frac{ 1 }{ 2 }\cos2x +c)\]

Answer 10

Yes, looks good.
Maybe call the 1/cosx uhh secx and distribute:
\[\large\rm y=\frac12\cos2x~\sec x+C \sec x\]But that's not super important.
Yay good job.

Answer 11

yayy

Answer 12

zeppers check my work

Answer 13

@Zepdrix

Answer 14

Yay good job

Answer 15

yayy