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Mathematics 18 Online
Pixel:

http://prntscr.com/iet235

Pixel:

@563blackghost

Pixel:

@Shadow

Pixel:

ouu

notdude:

We want to get rid of a variable here too, since 6 and 4 are easier numbers to find common factors from, lets get rid of y

Pixel:

12?

notdude:

Right, so what times 6 gives you 12? What times 4 gives you 12?

Pixel:

2 an 3

notdude:

So you would multiply each equation respectively \(\color{red}{-2(}13x-6y=2\color{red}{)}\\ \color{red}{-3(}3x-4y=-10\color{red}{)}\)

Pixel:

-26x-12y=-4 -9x-12y=30

Pixel:

+12y*

Pixel:

miss pushed

notdude:

Ah that was my mistake only one of them should be multiplied by a negative

notdude:

This \(-26x-12y=-4\\ -9x+12y=30\) Or this \(-26x+12y=-4\\ -9x-12y=30\)

Pixel:

-35x=26

notdude:

No, I am just telling you to chose one

Pixel:

segundo

notdude:

Ah crap, I made another mistake

Pixel:

im also practicing my spanish lel

notdude:

Lets do this one (this is what I was doing for the second one) \(\color{red}{-2(}13x-6y=2\color{red}{)}\\ \color{red}{3(}3x-4y=-10\color{red}{)}\)

Pixel:

-26x+12y=-4 9x-12y=-30

Pixel:

-17x=-30

Pixel:

that isnt right o~O

notdude:

Add -30 and -4

Pixel:

x=2

notdude:

Now substitute that into one of the equations

Pixel:

13x-12y=2

notdude:

\(13x-6y=2\) Not the right equation lol

Pixel:

"one of the equations"

Pixel:

o wait

notdude:

From the problem

Pixel:

13x-24y=2

Pixel:

now im confused XD

notdude:

\(13x-6y=2\\ 3x-4y=-10\)

Pixel:

3x-8y=-10

notdude:

Where did you get the 8 from?

Pixel:

*facedesk*

Pixel:

26x-6y=2

notdude:

Just chose one of the equations I just wrote lol

notdude:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @notdude \(13x-6y=2\\ 3x-4y=-10\) \(\color{#0cbb34}{\text{End of Quote}}\)

Pixel:

seufhfbefjiokeesfefaf e.e the second one

notdude:

\(3x-4y=-10~~~~~~~~~~~x=2\) Substitute \(3(2)-4y=-10\) Now solve that

Pixel:

6-4y=-10 -4y=-16 y=4

notdude:

So... \((2,4)\)

Pixel:

kill me the last one has fractions

notdude:

There is a trick to get rid of fractions

Pixel:

"fraction buster"

notdude:

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