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@563blackghost
@Shadow
ouu
We want to get rid of a variable here too, since 6 and 4 are easier numbers to find common factors from, lets get rid of y
12?
Right, so what times 6 gives you 12? What times 4 gives you 12?
2 an 3
So you would multiply each equation respectively \(\color{red}{-2(}13x-6y=2\color{red}{)}\\ \color{red}{-3(}3x-4y=-10\color{red}{)}\)
-26x-12y=-4 -9x-12y=30
+12y*
miss pushed
Ah that was my mistake only one of them should be multiplied by a negative
This \(-26x-12y=-4\\ -9x+12y=30\) Or this \(-26x+12y=-4\\ -9x-12y=30\)
-35x=26
No, I am just telling you to chose one
segundo
Ah crap, I made another mistake
im also practicing my spanish lel
Lets do this one (this is what I was doing for the second one) \(\color{red}{-2(}13x-6y=2\color{red}{)}\\ \color{red}{3(}3x-4y=-10\color{red}{)}\)
-26x+12y=-4 9x-12y=-30
-17x=-30
that isnt right o~O
Add -30 and -4
x=2
Now substitute that into one of the equations
13x-12y=2
\(13x-6y=2\) Not the right equation lol
"one of the equations"
o wait
From the problem
13x-24y=2
now im confused XD
\(13x-6y=2\\ 3x-4y=-10\)
3x-8y=-10
Where did you get the 8 from?
*facedesk*
26x-6y=2
Just chose one of the equations I just wrote lol
\(\color{#0cbb34}{\text{Originally Posted by}}\) @notdude \(13x-6y=2\\ 3x-4y=-10\) \(\color{#0cbb34}{\text{End of Quote}}\)
seufhfbefjiokeesfefaf e.e the second one
\(3x-4y=-10~~~~~~~~~~~x=2\) Substitute \(3(2)-4y=-10\) Now solve that
6-4y=-10 -4y=-16 y=4
So... \((2,4)\)
kill me the last one has fractions
There is a trick to get rid of fractions
"fraction buster"
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