http://prntscr.com/iete9t
@notdude
That was faster than expected
qazwsxedcrfvtgbyhnujmik,ol.p;/\
dont mind that ^
i copy the print screen
\(\large{\frac72x-\frac12y=\frac92}\) If you want to get rid of fractions you can multiply by a common denominator, in this case it is 2 \(\large\color{red}{2(}{\frac72x-\frac12y=\frac92}\color{red}{)}\\ ~\\ => ~7x-1y=9\)
e.e i forgot how to meth
I STG
XD
doesnt it cancel the denominator
Do you want me to review on how to do this? \(\large\color{red}{2(}{\frac72x-\frac12y=\frac92}\color{red}{)}\)
7x-y=9?
deed i do it right
Yes x'D
i can math
both y are negative
Right so we need to multiply one of the equations by a negative to get a positive
\(7x-y=9\) or \(3x-y=5\)
Choose one to multiply by a negative
first
\(\color{red}{-1(}7x-y=9\color{red}{)}\)
-7x+1=-9
-4x=-4
x=1
1-y=5
-y=4
y=-4
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Pixel 1-y=5 \(\color{#0cbb34}{\text{End of Quote}}\) Correction: \(3(1)-y=5\)
3-y=5 -y=2 y=-2
Right, so.. \((1,-2)\)
100% ty notdude
You're welcome
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