What is the median? {12,15,18,20,22,23,24,40,45}
Median - To find the medium list all the numbers in correct order, being sure to include an doubles. Then find the middle number. If there is an odd amount of numbers - the medium is the middle number. If there is an even amount the medium is found by adding the middle two numbers together and dividing by 2. The resulting number is the medium.
22
I'm about to work it out
thanks you guys are the best
it would be 22
I already said that.
can i ask you guys one more question?
yes
okay, What is the first quartile, Q1, of the data set? {36,45,79,80,82,85,90} please don't think i'm stupid i'm just not good at this subject.
Oof. Quartiles aren't my thing either.
same page here
hold on let me work it out
It's fine! That's what we're here for is to help guide you to the answer. You're not dumb if you're asking a question ¯\_(ツ)_/¯
thanks
Quartile Q1: 62 Quartile Q2: 80 Quartile Q3: 83.5
and your not stupid; i need help on ALOT of things as well
Wait show her how you got it please @getlikeliyiah
thnks
wait i don't have 62 as an answer
Order the data from least to greatest. Find the median of the data set and divide the data set into two halves. Find the median of the two halves.
okay
To find the median number: Put all the numbers in numerical order. If there is an odd number of results, the median is the middle number. If there is an even number of results, the median will be the mean of the two central numbers.
so would it be 36 or 45
yes
36
45
alright thanks do any of you do k12 in 6th grade
your welcome, and no im a Sophmore 10th grade
Are you guys finding the median or working on the second question?
i never did k12 , do you?
yup and were on the same question.
i meant to say the second question sorry
It's fine. Good work :P
@shasha12 do you need any more help?
um yes one more
okay what is it ?
okay hold on right quick
@shasha12 is 20 one of your answer choices??
yes that is what i was thinking too
okay , well thats what i got
alright thanks for everything
No problem, glad i could help
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