Question

Geometry help please?

Answer 1

i used to know how to do this ;-;. I'm sorry i can't help you

Answer 2

@563blackghost @dude

Answer 3

It's alright @Pixel, thank you though anyways. :)

Answer 4

Well, the first one is literally given, so you just write 'given'.

The second one is something called Vertical Angle Theorem

Where angle A=A', and angle B=B'.

Now that you know 2 angles are the same for ABC and DBE, you use something called the Angle-Angle Postulate to prove 2 triangles are SIMILAR. The teacher taught you this right?

Answer 5

Yes they did, but just a heads up, I missed out on 2 years of math so im behind in the know how department. If you're able to, could you help me with 2 more problems please? @mhchen

Answer 6

yah just post them

Answer 7

Thanks so much.

Answer 8

Okay, so it looks like they put numbers on 2 sides of both triangles, and they give you an angle.

So we're gonna try to prove it using the Side-Angle-Side Postulate...

Answer 9

Okay

Answer 10

Okay, so it shows us that there's a right-angle on the top, and it's connected with both triangles. So we can already say that there's a congruent angle.

Now we need to determine if the 2 sides have the same ratio...

Answer 11

Basically,

Answer 12

So as you can see
the 12 on the left triangle, is like the 6 on the right triangle.
the 18 on the left triangle, is like the 8 on the right triangle.

But 12/6 = 2
and 18/8 = 2.25

So they're different

Answer 13

If they had the same ratio, then they would be similar by Side-Angle-Side,
but since they're different, they are NOT similar triangles.

Answer 14

Okay I understand, so the would be that they are not similar.

Answer 15

Okay so the 2 similar triangles are like this:



You basically set up this ratio:

\[\frac{5}{7} = \frac{x}{28}\]

Can you solve that?

Answer 16

x=20

Answer 17

Yeah. That's basically it

Answer 18

awesome, thank you so much for the help i really appreciate it