A chocolate bar measures 50 mm wide, 90 mm long, and 3 and 1 over 2 mm high. Will’s Wrapping Company is making a wrapper to cover the chocolate bar. Use the correct net and determine how much paper will be needed to make the wrapper. The net of a square prism with a height of 50 millimeters, a length of 90 millimeters, and a width of 3 and 1 over 2 millimeters. Will’s Wrapping Company needs 4,640 mm2 of paper to wrap the chocolate bar. Will’s Wrapping Company needs 4,990 mm2 of paper to wrap the chocolate bar. Will’s Wrapping Company needs 9,980 mm2 of paper to wrap the chocolate bar. Will’s Wrapping Company needs 19,960 mm2 of paper to wrap the chocolate bar.
"and 3 and 1 over 2 mm high" I'm not sure what this means... what are the 3 and the 1, and is this exactly how it's worded on the original page?
thats the image for it
Oh, so the 3 and 1 over 2 is 3 1/2 :P
?
\[3\frac{ 1 }{ 2 }\]
Ok, so I think the best way the solve the would be to seperate the rectangles, find the surface area of each one, and add it up.
do you have any question i could help you with?
Nah, but do you understand what to do on this?
no
this is the one i chose Will’s Wrapping Company needs 4,990 mm2 of paper to wrap the chocolate bar.
I don't think that's right
oh
You would multiply 90mm by 50 mm, then multiply that by 2 since there's two rectangles of the same size
ok so 90 x 50 x 2?
The for the outer 3 "flaps" (Not the inner one, since that was counted in one of the two bigger rectangles) you'd multiply their length (3 1/2 mm) by their width (50mm)
the answer is 9,000?
Then add it all together
Not 9000, we still have the outer flaps
so what do we do with the outer flaps?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @ElectricImpurity The for the outer 3 "flaps" (Not the inner one, since that was counted in one of the two bigger rectangles) you'd multiply their length (3 1/2 mm) by their width (50mm) \(\color{#0cbb34}{\text{End of Quote}}\)
9000 x 2 ?
Read what I just posted :P
so the answer is 9,980?
Yep!
YES thank you!
could you help me on anothother?
Sure
Use a net to find the surface area of the right triangular prism shown below: Three rectangles next to each other with a width of 7 feet. The first and second rectangles length are unknown, and the last is 10 feet long. There are two right triangles above and below the last rectangle. One is labeled with a base of 6 feet and a height of 8 feet. 198 square feet 216 square feet 270 square feet 280 square feet
First, see the two triangles? The add up to a rectangle, so their combined area is 48 feet
then it's 48 x 3?
Where did the 3 come from?
i thought that since i...... Nvm
Oh, ok. I'm not sure if the triangles equal the other rectanges EXACTLY. I think you might be right though
so the answer is 198?
Well, no. The rectangles area is 70 feet, while the combined triangles equal 48 feet
There's still one more rectangle, though.
so 216 or 270?
Pretty sure the last rectangle is 42 feet, so 188 + 42
No, that's not right...
yea the answer to that is 230 not ans answer for the question
Ah, maybe the two bigger rectangles aren't equal
do you have discord?
Yep
me to
(Discord username is the same as on here :P) Oh now I see, I measured the rectangle wrong, it's actually 7 x 8, the correct answer is 216.
the name is the same on here
thanks
No problem
i though it was between 216 and 270
could you help me on 2 more?
Alright :P
:D
Which net represents the pyramid below?
not this one
A square pyramid is shown. What is the surface area? A square based pyramid, with bases labeled 3.5 centimeters and side length of triangle labeled 7 centimeters. 19.25 cm2 30.625 cm2 49.625 cm2 61.25 cm2
Hello?
im going to submit the exam now
I GOT AND F NOOOOO
where did you go???
ok i'll meet you on discord
what your # number?
mine is #1108
hey
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