Question

Geometry question, please help.

Answer 1

How do you think we should tackle this?

Answer 2

counting the boxes?

Answer 3

Hmm, which ones

Answer 4

the whole ones

Answer 5

the ones inside the shape

Answer 6

What shape?

Answer 7

We have a polygon, but there are shapes within the polygon.

Answer 8

VEDR is 30 I just can't figure out for the triangle VRM

Answer 9

Did you count all the boxes in VEDR? ._.

Answer 10

yes

Answer 11

What shape is VEDR?

Answer 12

rectangle

Answer 13

The area of a rectangle is solved by multiplying it's length by it's width.

Line ED is 6 blocks long, like DR is 5 blocks long.

5 x 6 = 30

You don't need to count all the boxes xD

Answer 14

This assignment is meant to test your knowledge of shapes and what formulas apply to them

Answer 15

Now we have the area of the rectangle, but we need the area of the triangle in order to solve. How do you think we do that one?

Answer 16

multiply the length of the sides

Answer 17

What sides?

Answer 18

VM and MR

Answer 19

and VR

Answer 20

Hmm, that wouldn't give us the area of the triangle. Do you know the formula for the area of a triangle?

Answer 21

\[A = \frac{ base \times height }{ 2 }\]

Answer 22

okay

Answer 23

How would we apply that here?

Answer 24

3x5/2?

Answer 25

You're breaking it up into two triangles?

Answer 26

how would you do it then

Answer 27

What is the base of the triangle?

Answer 28

3 im assuming

Answer 29

What line is the base of the triangle?

Answer 30

VM?

Answer 31

how long is it then?

Answer 32

Since it isn't a straight line, we can't use it. We can use the distance formula to solve for it, but that is a lot of work that we don't need to do.

Could interpret line VR as the base?

Answer 33

this is supposed to be a 5 question quiz that takes no longer then 15 minutes. we've been on this question for 30 minutes now. i dont have time to be sitting here for 2 hours just to be able to get the answer right. could you maybe hurry up explaining please? you could have given me the correct base 10 minutes ago. and yes

Answer 34

VR is the base. Count how many boxes 'long' it is, and you get 6. If that's the base, then point M is the highest point. Count how high(from point M to (-2, 2), and you get 3.

\[A = \frac{ base \times height }{ 2 }\]

\[A = \frac{ 6 \times 3 }{ 2 }\]

\[A = \frac{ 18 }{ 2 } = 9\]

We could have solve it your way, and separated it into two triangles. It's more work, but we could use it to check ours.

First triangle, V, M, (-2, 2)

Base = 1, Height = 3

\[A = \frac{ 3 \times 1 }{ 2 } = 1.5\]

Second Triangle, M, R, (-2, 2)

Base = 5, Height = 3

\[A = \frac{ 5 \times 3 }{ 2 } \frac{ 15 }{ 2 } = 7.5\]

7.5 + 1.5 = 9

9 + 30 = 39units

Answer 35

Thank you