hardlyhuman:

Geometry question, please help.

3 weeks ago
hardlyhuman:
3 weeks ago

Shadow:

How do you think we should tackle this?

3 weeks ago
hardlyhuman:

counting the boxes?

3 weeks ago
Shadow:

Hmm, which ones

3 weeks ago
hardlyhuman:

the whole ones

3 weeks ago
hardlyhuman:

the ones inside the shape

3 weeks ago
Shadow:

What shape?

3 weeks ago
Shadow:

We have a polygon, but there are shapes within the polygon.

3 weeks ago
hardlyhuman:

VEDR is 30 I just can't figure out for the triangle VRM

3 weeks ago
Shadow:

Did you count all the boxes in VEDR? ._.

3 weeks ago
hardlyhuman:

yes

3 weeks ago
Shadow:

What shape is VEDR?

3 weeks ago
hardlyhuman:

rectangle

3 weeks ago
Shadow:

The area of a rectangle is solved by multiplying it's length by it's width. Line ED is 6 blocks long, like DR is 5 blocks long. 5 x 6 = 30 You don't need to count all the boxes xD

3 weeks ago
Shadow:

This assignment is meant to test your knowledge of shapes and what formulas apply to them

3 weeks ago
Shadow:

Now we have the area of the rectangle, but we need the area of the triangle in order to solve. How do you think we do that one?

3 weeks ago
hardlyhuman:

multiply the length of the sides

3 weeks ago
Shadow:

What sides?

3 weeks ago
hardlyhuman:

VM and MR

3 weeks ago
hardlyhuman:

and VR

3 weeks ago
Shadow:

Hmm, that wouldn't give us the area of the triangle. Do you know the formula for the area of a triangle?

3 weeks ago
hardlyhuman:
3 weeks ago

Shadow:

\[A = \frac{ base \times height }{ 2 }\]

3 weeks ago
hardlyhuman:

okay

3 weeks ago
Shadow:

How would we apply that here?

3 weeks ago
hardlyhuman:

3x5/2?

3 weeks ago
Shadow:

You're breaking it up into two triangles?

3 weeks ago
hardlyhuman:

how would you do it then

3 weeks ago
Shadow:

What is the base of the triangle?

3 weeks ago
hardlyhuman:

3 im assuming

3 weeks ago
Shadow:

What line is the base of the triangle?

3 weeks ago
hardlyhuman:

VM?

3 weeks ago
hardlyhuman:

how long is it then?

3 weeks ago
Shadow:

Since it isn't a straight line, we can't use it. We can use the distance formula to solve for it, but that is a lot of work that we don't need to do. Could interpret line VR as the base?

3 weeks ago
hardlyhuman:

this is supposed to be a 5 question quiz that takes no longer then 15 minutes. we've been on this question for 30 minutes now. i dont have time to be sitting here for 2 hours just to be able to get the answer right. could you maybe hurry up explaining please? you could have given me the correct base 10 minutes ago. and yes

3 weeks ago
Shadow:

VR is the base. Count how many boxes 'long' it is, and you get 6. If that's the base, then point M is the highest point. Count how high(from point M to (-2, 2), and you get 3. \[A = \frac{ base \times height }{ 2 }\] \[A = \frac{ 6 \times 3 }{ 2 }\] \[A = \frac{ 18 }{ 2 } = 9\] We could have solve it your way, and separated it into two triangles. It's more work, but we could use it to check ours. First triangle, V, M, (-2, 2) Base = 1, Height = 3 \[A = \frac{ 3 \times 1 }{ 2 } = 1.5\] Second Triangle, M, R, (-2, 2) Base = 5, Height = 3 \[A = \frac{ 5 \times 3 }{ 2 } \frac{ 15 }{ 2 } = 7.5\] 7.5 + 1.5 = 9 9 + 30 = 39units

3 weeks ago
hardlyhuman:

Thank you

3 weeks ago