Question

Amelia rolls two fair number cubes numbered from 1 to 6. She first defines the sample space as shown below:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

Based on the sample space, what is the probability of getting a total of 4?

6 over 36
5 over 36
4 over 36
3 over 36

Answer 1

there are 36 total outcomes

count the number of outcomes where the sum of the two numbers in parentheses is exactly 4

then it's just (that number)/36

Answer 2

is there a exact answer you can give?

Answer 3

it is a website policy not to give out direct answers here

simply look at the possible outcomes, count the number of outcomes where the sum of the two numbers is 4

example: (1,3)