A candy bar box is in the shape of a triangular prism. The volume of the box is 1,200 cubic centimeters. A triangular prism is shown with base of triangle labeled 10 cm, sides of the triangles labeled 13 cm, and length of the box equal to 20 cm. Part A: What is the height of the box? Show your work. (5 points) Part B: What is the approximate amount of cardboard used to make the sides of the candy box? Explain how you got your answer. (5 points)
please help
@Ultrilliam
@JustSaiyan
@ThisGirlPretty
@Ultrilliam
pls help
@eatsalad
The easiest way to solve for the volume would be to use the triangle as the base. Then 20cm would be the height.
Proven by: \[A _{T} = \frac{ 13 \times 10 }{ 2 } = 65\] \[V = 65 \times 20 = 1300cm^3\]
So I would use 20cm as the height of the box.
but the volume is 1200 not 1300
That doesn't make sense. The height of the box is 20cm. If you find the area of the triangle, then multiply it by 20, you could get the volume ._.
but i already have the volume, i just need the height
and part b
Lets see if salad has something c;
A V=1/2*Base area*H x=height 1/2*10*x*20=1200 solve x=12
wow, got anything for part b???
Doesn't make any sense though when they give us 13.
Must be a typo
In such a case I would have solved it the same way salad. You're good.
b 13+10*20=213
Or 13+13*20
wow, your really good
wait, which one???
Yeah i think it would be 13+10*20
Oh, facepalm, 13 is the side of the triangle, not height, LOL
okay, thank you!!!
If not 13+10*20 Then it would be 13+13*20
yw
You would need the area of the two triangles, two side rectangles, and then bottom rectangle. \[T = (13 \times 10) + (13 \times 20 \times 2) + (10 \times 20)\]
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