Question

In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 3x – 3, and HE = 5y + 4. Find the values of x and y.
x = 5, y = 12
x = 5, y = 9
x = 4, y = 9
x = 9, y = 4***** Is this right?

Answer 1

@Shadow

Answer 2

\[DH = HF\]
\[x + 3 = 3y\]
\[x = 3y - 3\]

\[GH = HE\]
\[3x -3 = 5y + 4\]

Input x

\[3(3y -3) - 3 = 5y + 4\]
Solve
\[9y - 9 - 3 = 5y + 4\]
\[4y - 12 = 4\]
\[4y = 16\]
\[y =4\]

Input y into first equation

\[x + 3 = 3(4)\]
\[x + 3 = 12\]
\[x = 9\]

Answer 3

Okay I was right, thank you!

Answer 4

No problem