Question

Helppleaseee

Answer 1

@Vocaloid

Answer 2

theta is acute, so we're in quadrant I

try drawing a right triangle in quadrant I, labeling the opposite and hypotenuse of theta, and then calculating cot

Answer 3

5/12

Answer 4

yeah 5/12 is what i got too awesome

Answer 5

cos t = 4 / 5

Answer 6

well done

Answer 7

and

Answer 8

30.9

Answer 9

if cot(theta) = 1.5 we can take the arccot of each side to get theta, it's a bit closer to 33.69 degrees

Answer 10

oh okay so for the second one its 33.69 degrees is the first one correct

Answer 11

yes

Answer 12

have you tried sketching a triangle and figuring out what ratio to use?

Answer 13

we can use the draw tool

Answer 14

let's let the right leg be the lamp, let's put the professor 10 feet away from the lamp like so

Answer 15

then, his shadow is 8 feet away from there, so

Answer 16

elevation from shadow to the top of the lamp is 40 degs so:

Answer 17

what ratio would we use to find the length of the street lamp?

Answer 18

um sin

Answer 19

which ratio uses the opposite side, the adjacent side, and the angle?

Answer 20

tan

Answer 21

good, so set up the calculation for tan and find the height of the street lamp

Answer 22

wait so 18/?

Answer 23

so actually opp/18

Answer 24

good, tan(40) = opposite/18, calculate opposite

Answer 25

15.10

Answer 26

good, units are feet so 15.10 feet

Answer 27

try sketching a right triangle for 21 and label the appropriate sides and angle

Answer 28

20sin30 or 20(1/2) or 10ft.

Answer 29

good, 10ft = your ans