Help
@tigerlover
@563blackghost
@Sam
@Vocaloid
Alright. What you need to do is find S and put it in your calculator with the symbol [\sin]\
Oh my ^^;
Hmmm
I have a graphing calculator
Use google to use the calculator
Okie so how do I do this Or better yet what do I do first
Alright, do you know the degree of the other angles?
68 and 60, right?
It looks like those are the lines measurments. Try to find the angles mesurments.
How do I do that?
What's the full degree of a Triangle?
180
Alright. So we know that one angle is 90. Now we need to find the rest of the angle.
Okie, what do I do?
@Tranquility
@Warriorz13
@Shadow
Have you ever heard of SOH CAH TOA?
Nope
So, that's really the basics when you learn about sin, cos, or tan. \( \sin \theta = \frac{opposite}{hypotenuse}\) \( \cos \theta = \frac{adjacent}{hypotenuse}\) \( \tan \theta = \frac{opposite}{adjacent}\)
So do I do this? sin 0 = 68/60?
Sorry, mines more complicated ^^;
Thanks Tranquility
Its alright, I assumed you were busy
I know you are sometimes and I can be a burden
No its alright ^^
I hate to bother
No, so for sin you simply take the sides that are opposite to the angle and the hypotenuse. For example, if we had this triangle: |dw:1520441396565:dw| The side opposite of the angle \(\theta\) is 3. And the hypotenuse is 5. Remember, the hypotenuse is the side opposite the 90 degree angle. It's the longest side in a right angle triangle. And so what we get from the example is \(\sin \theta = \frac{3}{5}\)
So in this case sin 0 = x/68?
Yes, good job! However we can calculate the opposite side using the Pythagorean theorem. Do you remember what that is?
Not exactly, I'm very stupid at Math
|dw:1520441989862:dw| a^2 + b^2 = c^2 We can use that to find the value of one side knowing two sides of a right angle triangle
So a^2+68^2+60^2?
Wait 60 is bottom and 68 is the top
There's an equal sign. Remember the two legs of the triangle is going to be a and b, and the hypotenuse is c
Wait, how would I write this out? I'm lost
Labeling is my weakness, whereas solving is no problem
For your triangle, is 60 or 68 the hypotenuse of the triangle?
Um both are equal lengths
60 and 68 are the lengths of the side of the triangle. Remember, the side opposite is the hypotenuse What is the length of the hypotenuse https://assets.questioncove.com/attachments/1520436066-5aa003555dcbc1fbfeec7400-Screenshot_84.png
90?
The numbers that are next to the sides are the length. 90 is the angle value
60
|dw:1520443199609:dw|
Gosh sorry to keep doing this 68 I meant
Ok so a^2 + b^2 = c^2 c is the hypotenuse which means it's 68 And you can put 60 as either a or b, it doesn't really matter and just solve for the other letter
I got B=0
Try again a^2 + 60^2 = 68^2 Solve for a. First take the squares, and then move everything to one side and then you'll need to square root.
I thought you said it didn't matter if it was a or b
a=32,-32
It doesn't matter if you decide to make a = 60 or b = 60, but we need to solve for the other side. Also, since length is a positive thing, we take the positive value. So know we know that the opposite side is 32. Can you find what the final answer is now?
32/68?
Perfect, great work!
Thanks. I have to go now, thanks
No problem
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