Question

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Answer 1

\[A = 154\]
\[l = w + 3\]
\[A = l \times w\]
\[154= (w + 3) \times w\]
\[154 = w^2 + 3w\]
\[0 = w^2 + 3w - 154\]
Factor out
\[0 = (w + 14)(w - 11)\]

\[w = -14, 11\]

Since measurements of rectangles can't be negative, w = 11.

Checking Work:
\[l = w + 3\]
\[l = 11 + 3\]
\[l = 14\]

\[A = l \times w\]
\[A = 14 \times 11\]
\[A = 154\]