Peter is giving marbles to some children at a carnival. He has 5 red marbles, 4 blue marbles, and 3 yellow marbles. If Peter selects a marble randomly without looking, what is the probability that he will give a blue marble to the first child and then a yellow marble to the second child?

4 over 12 plus 3 over 12 is equal to 7 over 12
4 over 12 plus 3 over 11 is equal to 80 over 132
4 over 12 multiplied by 3 over 12 is equal to 12 over 144
4 over 12 multiplied by 3 over 11 is equal to 12 over 132

Question

Peter is giving marbles to some children at a carnival. He has 5 red marbles, 4 blue marbles, and 3 yellow marbles. If Peter selects a marble randomly without looking, what is the probability that he will give a blue marble to the first child and then a yellow marble to the second child?

4 over 12 plus 3 over 12 is equal to 7 over 12
 4 over 12 plus 3 over 11 is equal to 80 over 132
 4 over 12 multiplied by 3 over 12 is equal to 12 over 144
 4 over 12 multiplied by 3 over 11 is equal to 12 over 132

AnimeGhoul8863 · Answer

im sorry but i dont know @Vocaloid hopefully he can help

Vocaloid · Answer

total marbles = 5 red + 4 blue + 3 yellow

for giving a blue marble to the first child, the probability would be

(blue/total)

for giving a yellow marble to the second child, you must subtract 1 from the total (since one marble was already given away) and then find

(yellow/new total)

then, since it wants the probability of both events, multiply

(blue/total)*(yellow/new total)