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Isabella is solving the equation 4x^2=13x−3 with the quadratic formula. Which values could she use for a, b, and c? a = 4, b = 3, c = −13 a = 4, b = −3, c = 13 a = 4, b = 13, c = −3 a = 4, b = −13, c = 3
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@dude
We have to set the equation equal to 0
A den?
No lol
;-;
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mk gimme a sec
AH C
Welp \(4x^2=13x−3\) You want to have the equation set to 0 Subtract 13x and add 3 on both sides! \(4x^2-13x+3=0\) This equation is written in \(ax^2+bx+c\) So... \(a=1,~b=-13,~c=3\)
but there is no a=1 .-..
\(a=4\) My mistake x'D
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I SAID THAT YOU DING DONG
That is answer choice D.
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