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Geometry question, please help!!
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@Shadow
Do you know the formula for inscribed angles?
no
Okay
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\[Angle = \frac{ 1 }{ 2 }Arc\] My bad this is the formula B is an inscribed angle, lets solve for its arc \[116 = \frac{ 1 }{ 2 }ADC\] \[232 = ADC\] Arc ADC = 232
A circle is made up of 360 degrees 360 - 232 = 128 That means arc ABC = 128 degrees \[Angle = \frac{ 1 }{ 2 } Arc\] \[x = \frac{ 1 }{ 2 }128\] \[x = 64\]
Angle A, the angle we are trying to solve for, is equal to 2x - 40. \[A = 2x - 40\] \[A = 2(64) - 40\] \[A = 128 - 40\] \[A = 88 \]
Thanks so much :)
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