Question

Help

Answer 1

any attempts so far? I would suggest trying to find x-values where the function equals 0, 1, -1 for sin and cos, then connecting them with a smooth line

Answer 2

actually you already graphed sin earlier so you can just copy it over for 4

Answer 3

I actually submitted that practice assignment so :/

Answer 4

well, ok, let's start with cos and get back to that

what x-value would cos(x) = 1

Answer 5

1

Answer 6

hm, not quite

Answer 7

2pi n

Answer 8

sorry

Answer 9

yeah nvm ur right

Answer 10

let's plot (0,1) and (-2pi,1), etc.

Answer 11

what about x values when cos(x) = 0?

Answer 12

unit circle again

Answer 13

x values are pi/2 and 3pi/2 so let's plot these on our graph

Answer 14

Yeah im srry I was looking for a blank graph I could work off of on google couldn't find one

Answer 15

then cos(x) = -1 on odd multiples of pi (according to the unit circle so)

Answer 16

right

Answer 17

as a short-cut method for graphing sin(x) you just need to shift cos over by pi/2 units

Answer 18

for 5) csc(x) [I know i'm skipping around but it's easy to explain csc right after graphing sin(x)

Answer 19

you just take the sin graph, draw the asymptotes where the zeros of sin are, then draw the loops going away from the vertices like that

Answer 20

for 3) remember what the shape looks like / where the asymptotes are?

Answer 21

for tan(x) the asymptotes are pi*n + pi/2 , sketch the asymptotes then fill in the rest of the tan graph

Answer 22

Yeah I'm getting it, ugh sorry you are having to do all the work :/

Answer 23

okay for the fourth

Answer 24

4 is just sin(x) which is this

Answer 25

it also asks for the zero's/asymptotes for the graph so be sure to label those