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9th Grade Quadratic Equations. http://prntscr.com/iwtnoa
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I think the equation would be x(x+6)=56
Which would turn into x^2 + 6x = 56
Subtracting 56 from both sides you get x^2 + 6x - 56
Formula for the Area of a Triangle \[A = b \times h \times \frac{ 1 }{ 2 }\] Where b = base h = height Let x = base Therefore h = x + 6 They give us A = 56 So we input those into the formula and we get\[56 = x(x + 6) \times \frac{ 1 }{ 2 }\]
Oh!
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You forgot the 1/2
I forgot 1/2
Okay so then it'd be \[56 = 1/2x^2 + 3x\]
mhm
So after inputting this into the quadratic formula (too hard to put on here XD) I'd get 8 and -14. 8 makes sense because you can't have a negative length.
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mhm
Thank you kind sir.
No problem
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