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Mathematics 18 Online
Aureo:

9th Grade Quadratic Equations. http://prntscr.com/iwtnoa

Aureo:

I think the equation would be x(x+6)=56

Aureo:

Which would turn into x^2 + 6x = 56

Aureo:

Subtracting 56 from both sides you get x^2 + 6x - 56

Shadow:

Formula for the Area of a Triangle \[A = b \times h \times \frac{ 1 }{ 2 }\] Where b = base h = height Let x = base Therefore h = x + 6 They give us A = 56 So we input those into the formula and we get\[56 = x(x + 6) \times \frac{ 1 }{ 2 }\]

Aureo:

Oh!

Shadow:

You forgot the 1/2

Aureo:

I forgot 1/2

Aureo:

Okay so then it'd be \[56 = 1/2x^2 + 3x\]

Shadow:

mhm

Aureo:

So after inputting this into the quadratic formula (too hard to put on here XD) I'd get 8 and -14. 8 makes sense because you can't have a negative length.

Shadow:

mhm

Aureo:

Thank you kind sir.

Shadow:

No problem

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