Question

True?

Answer 1

good

Answer 2

false

Answer 3

well done

Answer 4

well done

Answer 5

true

Answer 6

well done

Answer 7

C

Answer 8

hint - what's the trig function that describes those red lines? sin has a periodic pattern so that's not quite it

Answer 9

um tan?

Answer 10

good

so the blue line is 1, the red is tan, so what's the equation of the intersection?

Answer 11

B

Answer 12

awesome

Answer 13

C

Answer 14

hm. I'm not 100% sure but I think that's it too

Answer 15

D

Answer 16

not quite, look at the domain and range ,which trig function has range [-pi/2,pi/2] and domain (-1,1)

Answer 17

um B

Answer 18

really close but not quite, arccos(x) has a range of (0,1)

as a hint try looking up the graphs of each function [these are pretty hard to graph from memory tbh]

Answer 19

Ugh A

Answer 20

it's arcsin, you just gotta know these unfortunately

Answer 21

Im sorry

Answer 22

nah it's not a big deal, I barely remember these myself

Answer 23

any thoughts based on this?

Answer 24

oh infinite

Answer 25

notice how there's only one point for x = 3, so only 1 sol'n

Answer 26

aT/n

Answer 27

your software is interpreting t, a, and n as variables, try using arctan(x) as your notation

Answer 28

you have to plug in -1 for the x-value since we want arctan of -1

Answer 29

just try arctan(-1)

Answer 30

-1

Answer 31

ugh idk why im getting something diff

Answer 32

alternatively you can use the unit circle to find where sin/cos = -1

Answer 33

so -pi/4

Answer 34

for the answr

Answer 35

good

Answer 36

-5/12

Answer 37

good

Answer 38

Ugh have to redo it :/ got a 50% i wonder what I did wrong