help @vocaloid vectors
@Shadow
@Shadow @Shadow
\[D = \sqrt (x _{2-} x _{1})^2 + (y _{2} - y _{1})^2\]
D = the distance
b is answer
is3 a?
@Vocaloid
@Shadow
3) vector = terminal - initial select the answer choice that gives you <50,120>
they tell you the answer in question 4 lol
4 is a right because it would be th eopposite
yes that's correct
1: vector = terminal - initial so you would subtract the coordinates of B minus A
so b
good then for 2) you would take the coordinates of the answer from 1) and plug it into r = sqrt(x^2 + y^2) to find the magnitude gtg pretty soon, I have volunteer work to do
could you at least help with 2 more questions after this and I'll figure out my other lessons on my own
I have like 5 minutes so sure
c? for 2
hero can take over if he needs to
for the magnitude one? I got something a little different sqrt(6^2 + (-2)^2) = ?
3) is another terminal - initial one, plug in the options to see which one equals <-3,5>
i got a for 2
for 4) assume you start at <0,0> and calculate the magnitude of the vector between <0,0> and the final location, then see if the magnitude is above or below 7920 (the discounted rate)
yeah, I got a for 2) [the magnitude question]
gtg
so c for 3
How many questions do you have in total? @kaylak
just these last 2 unless I need help on another lesson I working to finish my class
so 3 is c right?
What last two? Can you post it in a different post?
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