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Mathematics 21 Online
kaylak:

help @vocaloid vectors

kaylak:

@Shadow

1 attachment
kaylak:

@Shadow @Shadow

Shadow:

\[D = \sqrt (x _{2-} x _{1})^2 + (y _{2} - y _{1})^2\]

Shadow:

D = the distance

kaylak:

b is answer

kaylak:

is3 a?

kaylak:

@Vocaloid

kaylak:

1 attachment
kaylak:

@Shadow

Vocaloid:

3) vector = terminal - initial select the answer choice that gives you <50,120>

kaylak:

they tell you the answer in question 4 lol

kaylak:

4 is a right because it would be th eopposite

Vocaloid:

yes that's correct

kaylak:

1 attachment
Vocaloid:

1: vector = terminal - initial so you would subtract the coordinates of B minus A

kaylak:

so b

Vocaloid:

good then for 2) you would take the coordinates of the answer from 1) and plug it into r = sqrt(x^2 + y^2) to find the magnitude gtg pretty soon, I have volunteer work to do

kaylak:

could you at least help with 2 more questions after this and I'll figure out my other lessons on my own

Vocaloid:

I have like 5 minutes so sure

kaylak:

c? for 2

kaylak:

hero can take over if he needs to

Vocaloid:

for the magnitude one? I got something a little different sqrt(6^2 + (-2)^2) = ?

kaylak:

1 attachment
Vocaloid:

3) is another terminal - initial one, plug in the options to see which one equals <-3,5>

kaylak:

i got a for 2

Vocaloid:

for 4) assume you start at <0,0> and calculate the magnitude of the vector between <0,0> and the final location, then see if the magnitude is above or below 7920 (the discounted rate)

Vocaloid:

yeah, I got a for 2) [the magnitude question]

Vocaloid:

gtg

kaylak:

so c for 3

Hero:

How many questions do you have in total? @kaylak

kaylak:

just these last 2 unless I need help on another lesson I working to finish my class

kaylak:

so 3 is c right?

Hero:

What last two? Can you post it in a different post?

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