Question

@shadow

Answer 1

Don't see a question. And @Hero is much smarter than me.

Answer 2

hero is about to leave

Answer 3

@Hero

Answer 4

I can help you later. Like in 3 + 1/2 hours maybe

Answer 5

@Tranquility

Answer 6

@Vocaloid

Answer 7

for 1) you just need to divide the vector by the magnitude to get the unit vector

Answer 8

b?

Answer 9

@Vocaloid

Answer 10

check your calculations again

magnitude = sqrt(5^2 + 3^2) = ?

Answer 11

a?

Answer 12

i know its a or d

Answer 13

you should have gotten sqrt(34) as the magnitude right? what happens when you divide <5,3> by sqrt(34) and rationalize the denominator?

Answer 14

so its d ?

Answer 15

good

2) vector = terminal - initial as usual, then convert to i and j notation

Answer 16

so c that's it

Answer 17

?

Answer 18

good, C

Answer 19

for 3) try converting both to vector notation <,> and subtracting them like a normal equation

so v = 6i - 4j becomes <6,-4> then find u - 2v

Answer 20

b i think Im making a mistake somewhere

Answer 21

just look at the x-coordinate for now

u - 2v becomes
-2 - 2(6) = ?

Answer 22

ah it's a I see my mistake now