Question

Math -

Answer 1

@dude

Answer 2

@dude stop doing meth

Answer 3

Bear Ill do meth if I want

Answer 4

Oh thats it mister. You just got the timeout chair

Answer 5

For the first question she can conclude ΔABC and ΔEDC are similar because they have equal angles.
ΔABC has \(\angle \)B = 90° and ΔEDC has \(\angle \)D = 90°.
\(\angle \)ACB in ΔABC = \(\angle \)DCE in ΔEDC (opposite angles)
(Which means that \(\angle \)E = \(\angle \)A as both triangles have angles which add to 180°.)

Answer 6

Mark, stop spamming. ._. I'm trying to understand and you're a distraction ._.

Answer 7

pfffft fine

Answer 8

For question 2)
If DE=32ft then (because the triangles are similar) we can use a proportion
\(\large \frac{AB}{BC}\) = \(\large \frac {DE}{CD}\)
\(\large \frac{AB}{100}\) = \(\large \frac {32}{22}\)
AB = 100 \(\large\cdot \frac{32}{22} \)
\(\therefore\) AB= 145ft

Answer 9

Thank you.

Answer 10

Sure :)