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What is the power of a lightbulb that has a current of 0.480 A at 120.0 V? 120/0.480=250
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P = IV so you would multiply not divide
120.0*0.480=57.6
good, units of power are W (watts) as usual
What is the voltage drop across a 40.0 Ω resistor that has a 0.350 A current?
40/0.350=114.3
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V = IR so once more you would multiply current and resistance not divide
40*0.350=14
good, units of potential drop is V as usual
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