Use the quadratic formula to solve x^2+6x=14. Show ALL work to receive FULL credit. Then describe the solution
@pillows, how far have you gotten with this one?
nowhere
Do you have the quadratic formula with you?
no
If you have a quadratic equation of the form \(ax^2 + bx + c = 0\), The quadratic formula to find \(x\) is \(x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
In other words, you have to make sure the given quadratic equation is in standard form first before determining the values of a, b, and c. What would be the first step in order to put the quadratic equation in standard form?
idk
They give you \(x^2+6x=14\). What do we need to do in order to make the right side equal zero?
@pillows are you watching TV or something?
oh sorry no i was emptying the garbage
and i really dont know what to do
Okay, so the first step is to subtract 14 from both sides of \(x^2 + 6x = 14\). What do you get after doing so?
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