The length of a rectangle is 3 more than twice the width. The area of the rectangle is 119 square inches. What are the dimensions of the rectangle? If x = the width of the rectangle, which of the following equations is used in the process of solving this problem? 2x2 + 3x - 119 = 0 3x2 + 3x - 119 = 0 6x2 - 119 = 0
@NOpanda14 @563blackghost
What is the formula for the area of a rectangle?
@JT
A=wl
I think
Correct, so do you know what the length and width are?
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They give us that the width is x. They also give that the length is 3 more than twice the width. \[W = x\] \[L = 2x + 3\] \[A =WL\] \[A = x(2x + 3)\] \[A = 2x^2 + 3x\] Hey also gave us the area of the rectangle, which is 119. \[119 = 2x^2 + 3x\] \[0 = 2x^2 + 3x - 119\]
They* On mobile lol
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