The solution to the equation is?
@dude I MESSED UP
What happened?
\[\frac{ 4x }{ 3 } = 2(x+9)\] -54 -27 -6.75 -4.5 27
Not a single one fit in... they were all wrong when I worked them out.
Want me to post all my work?
Hmm well lets solve this algebraically \(\large {\frac{4x}{3}}=2(x+9)\) Lets distribute the 2
|dw:1524090080393:dw|
Right \(\large {\frac{4x}{3}}=2(x+9)\) \(\large \frac{4x}{3}=2x+18\) To get rid of the fraction, we can multiply both sides of the equation by 3
|dw:1524090229016:dw|
Right \(4x=6x+54\) Now we want to get x on one side of the equation
|dw:1524090363363:dw|
|dw:1524090388092:dw|
Yes amd now lets divide by -2 on both sides =P
There is your answer
:0
I’m dumb...
To check \(\large \frac{ 4x }{ 3 } = 2(x+9)\\ \large \frac{ 4\cdot-27 }{ 3 } = 2(-27+9)\\ \large \frac{-108}{3}=2(-18)\\ \large\frac{-108}{3}=-36\\ -36=-36\)
Thank you!
14 more :/
Lets get to them :P and no prob!
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