Is anyone here good at Math?
No.
..
You asked a question and I answered...
:D
Whats the question
"Is anyone here good at Math?"
Kinda and kinda not
You need to identify which trig ratio you are using. You see that you have a known angle of 45 degrees, with an opposite side of \(\bf{6\sqrt{2}}\) and wanting to know of the hypotenuse. This means that you will use the sine ratio. \(\Large\bf{sin(45)=\frac{6\sqrt{2}}{x}}\)
I put that in and it was incorrect
what answer did you get?
Wait so I do the ratio? It'll be 36
It's not 36. Simplify the equation. \(\large\bf{6\sqrt{2} \div sin(45)=x}\) Plug it into your calculator.
I don't know how to put sin in my calculator
you should have a graphin calculator in order to geometry questions. Try using mathway.com , plug the equation and see what your answer is.
I used a different one, its equals 12
yea thats right
Just 2 more I need checked after this
Not quite. Since you know of the hypotenuse and want to know of the adjacent you use cosine. \(\large\bf{cos(39)=\frac{x}{17} ~~~\rightarrow~~~ 17 \times cos(39)=x}\)
ye just round to the nearest tenth.
13.20?
yup
Which ratio would you use?
Cos?
yea. So it is... \(\large\bf{cos(18)=\frac{x}{25}}\)
oh wait i didnt see your answer >.< so sorry you are right!
23.80
Rounded it already
your answer \(\bf{23.78}\) is correct >.< you have to round to hundreths not tenths.
Ohh
which do you think is the tan?
5?
5? There are 3 options....
I'm clueless, sorry
you got the cos one right. It's just sin and tan need to switch.
So 1,2,3
cos is 2, sin is 3, and tan is 1.
Okay thank you very much
no problem >.<
Join our real-time social learning platform and learn together with your friends!