Question

Help ~;-;~

Answer 1

\[(3x^-2y^3z^0)^3\]

Answer 2

X is ^-2

Answer 3

\[z^0 = 1 \]

Any number to the 0th power = 1, so you can basically cross it ou.

Answer 4

alright then

Answer 5

\[(3x ^{-2} y^3)^3\]
\[3^{3}x ^{-2 \times 3}y ^{3 \times 3}\]

Answer 6

The rest is pretty easy. Let me know what you get.

Answer 7

Good