A point is selected at random inside the given figure. What is the probability the point will be in the region labeled D? Choose your answer, as a fraction in simplest form. P(D) =
\(P(D) = \dfrac{\text{Area of region D}}{\text{Area of entire rectangular region}}\)
That's your hint
4/19
?
Mind explaining how you came up with that fraction?
Yah, 4 is Area of region D and 19 is I added all of the number and got 19....
BTW, @iosangel what is the formula for Area of a rectangle?
w*l
How do i ind the area of that? its split in halves
find*
What is the length and width of rectangle D?
3 and 4...
Oh lol, so 4 *3
Does 3 and 4 really represent the entire length and width of D? The length of D seems a lot longer than 4 to me.
Uh, 5?
Why do you think 5 represents the length of D?
I have no idea, but I think it would be 12 since 3*4 is 12... l*w.... right?
|dw:1524500723593:dw| that length is only 4? Really?
Ohh, its 9
Very good. So what is the area of D?
9
or 27
@Hero don't leave MEH~~~~~ ik I'm dumb, my teacher doesnt explain any math to me.......
Yes, The Area of D is 27 which would be the numerator of the fraction. Now for the denominator ... Can you calculate that?
I'll try....Width would be 5 and length would be 12?
and then 5*12?.....
Right?
Let me do some more highlighting
|dw:1524501381881:dw|
|dw:1524501395147:dw|
5 is the width and 3 is the length... so 15?
No, it isnt 15...
You figured out the correct answer for D. I wonder how you did that. The width of the entire rectangle is the same as the length of D
Oh yes
Or I should say the width of the BIGGEST* rectangle is the same as the length of rectangle D. Do you see that?
Anyway, I think you confuse yourself too easily. The hints I give are pretty clear.
It's be 9 then.....
Yes, and what about the length of the BIGGEST rectangle?
30
That's too big actually.
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