Factoring
@Hero im confused... I have to take a simplified problem and turn it back into a binomial.
Post one of the problems you're working on and we'll take it from there.
The expression \[x^2-6x+8\] is equivalent to (x+8)(x-1) (x-8)(x+1) (x+4)(x+2) (x+4)(x-2)
Okay, sorry, had to deal with chat issues, but anyway ...
What you want to do is take the original expression and "split the middle" term. I'll explain how to do that.
To split the middle term, you take the expression ax^2 + bx + c and you find two numbers that sum to get b yet those same two numbers multiply to get ac
That or you could try the F.O.I.L method on all of those terms.
Ha... kids..
FOIL scares meh
Except @tigerlover doing that does not help you learn how to factor.
Btw Enders, could you msg me? I want to apologize to you.
I unblocked you.
I like factoring, lemme draw it on my paper real quick.
@Hero
x^2 -6x +8 = ? you need getting two numbers with sum equal -6 and product equal +8 can you getting ?
I’m confused by your wording.
how can you making -6 assuming two numbers so that than you multiply these two numbers will get 8 ?
a+b=-6 a*b=8
Yes. -2+-4=-6 and -2*-4=8
exactly very nice and easy
so than now how can you factorizing x^2 -6x +8 = (x ... )(x ...)
you wrote above -2-4=-6 and -2*-4=8 this mean that you solved it right
multiply these please (x-2)(x-4) = ?
@EndersWorld do you understand it now ?
Not perfectly, I may stumble a bit but yes.
yes you made it right
x^2 +4x +4 = ? how you factoriz this ?
Lemme right it out.
i like seeing that you know the way
yes right but than my be there x^2 -4x +4 = ?
(x-2)(x+2)
in the second parentheses what is there plus or minus 2 ? bc i see plus 2
so than -2+2=0
two numbers with sum equal -4 and product +4 ?
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