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Mathematics 6 Online
Flamo:

Find the distance between the points (6, 5 sqrt(2) ) and (4, 3 sqrt (2) )

Flamo:

What Formula do you use here?

Angle:

|dw:1524720334712:dw|

Flamo:

o?

Angle:

I'm not sure if the sqrt(2) in your question is supposed to be there or not

Flamo:

\[(6, 5\sqrt{2} )\]

Flamo:

\[(4, 3\sqrt{2})\]

Angle:

ewww

Flamo:

Ye. That's how it looks.

Flamo:

Sadly

Angle:

ok so

Flamo:

Honestly Im Confused

Angle:

leg a = \(5\sqrt{2} - 3 \sqrt{2} = 2 \sqrt{2} \) leg b = 6 - 4 = 2

Flamo:

o

Flamo:

So the answer is \[2\]?

Angle:

well a^2 + b^2 = c^2

Flamo:

Wait or 2 sqrt 2?

Flamo:

o

Flamo:

So, \[2\sqrt{2}\] ^2 + 2^2 = c^2?

Angle:

yup I get what you mean ^_^

Flamo:

Okay, xD

Flamo:

Whats \[2\sqrt{2}\] to the power of 2?

Angle:

x^2 = x*x so \((2 \sqrt{2} )^2 =2 \sqrt{2}~~* ~~2 \sqrt{2}\)

Flamo:

So its 8?

Angle:

yes

Flamo:

o

Flamo:

8 + 4 = c^2

Flamo:

12 = c^2

Flamo:

\[\sqrt{12} \] =

Flamo:

Hm...

Flamo:

\[2\sqrt{3} \]?

Angle:

perfect :)

Flamo:

Ye! Ty!

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