Question

I’m confused *^*

Answer 1

\[(-x^2y^{-7}z^1)^2/]

Answer 2

Uhhhh...

Answer 3

\[(-x^2y^{-7}z^1)^2\]

Answer 4

\[(-x^2y^{-7}z^1)^2\]

Answer 5

Yea, that

Answer 6

First thing I would do since the whole thing is squared is this:
\((-x^2y^{-7}z^1)^2 = (-x^2y^{-7}z^1)(-x^2y^{-7}z^1)\)

Answer 7

Hopefully you understand why that is necessary.

Answer 8

Multiply everything?

Answer 9

Basically if you see a 2 outside the parentheses, it means to multiply whatever is in the parentheses twice.

Answer 10

The next step is to pair like terms together:
\((-x^2y^{-7}z^1)^2 = (-x^2y^{-7}z^1)(-x^2y^{-7}z^1)\)
\(=(-x^2)(-x^2) \cdot (y^{-7})(y^{-7})\cdot(z^1)(z^1)\)

Answer 11

Aren’t the two z’s useless because they are \[^1\] so they equal 1?

Answer 12

And then go from there. There are three things to know how to do
1. How to multiply two negative numbers
2. How to multiply two exponents
3. How to multiply negative exponents

Answer 13

Only in division will \(\dfrac{z}{z} = 1\). Multiplying two \(z\)'s is different.

Answer 14

Two negatives multiplying is a positive. And I believe you add the exponent.

Answer 15

Sounds good so far. What do you do with the negative exponents?

Answer 16

You add them and flip the sign to positive

Answer 17

Actually, here's the rule for negative exponents:
\(a^{-b} = \dfrac{1}{a^b}\)

In other words, expressions with negative expressions get converted to fractions.

Answer 18

That sounds... terrifying and painful..

Answer 19

It's neither painful or terrifying. Simply a rule to apply.

Answer 20

So... \[\frac{ 1 }{ y^7}\]

Answer 21

yes
\(y^{-7} = \dfrac{1}{y^7}\)

Answer 22

So I have it set up, now do I just combine like terms?

Answer 23

Yes, go ahead and attempt to finish this. Post your result below.

Answer 24

\[x^4\frac{ 1 }{ y ^{14}}\]

Answer 25

What happened to the z's? I tried to help you understand that you don't eliminate them. The rule for adding adding exponents still apply to the z's

Answer 26

I told you I’m not the brightest LOL

Answer 27

No spamming :0

\[x^4\frac{ 1 }{ y^14}z^2\]

Answer 28

When you express the result it should be expressed as one fraction with all the appropriate expressions in the numerator and denominator of the fraction.

Answer 29

Remember that \(a \times \dfrac{1}{b} = \dfrac{a}{b}\)

Answer 30

@EndersWorld I'm giving you an opportunity to express the result in the correct form.

Answer 31

\[\frac{ x^4z^2 }{ y^14 }\]

Answer 32

`\frac{ x^4z^2 }{ y^{14} }`

Answer 33

^Showing you the correct \(\LaTeX\) format for your expression.

Answer 34

Which produces this:
\(\dfrac{ x^4z^2 }{ y^{14} }\)

Answer 35

So I was right :0

Answer 36

Technically yes. Great job.

Answer 37

Hopefully doing that one helped clear up some of your "confusion"

Answer 38

Got a different type of radical next.

Answer 39

@ultrilliam

Answer 40

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Answer 41

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Answer 42

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predictable based on

Answer 43

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Answer 44

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Answer 45

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Answer 46

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Answer 47

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Answer 48

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Answer 49

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F

He

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Answer 50

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Answer 51

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Answer 52

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Answer 53

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Answer 54

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Answer 55

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Volume
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Answer 56

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Answer 57

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A.2/3x^-2+x+1
B.x^3+0x^2+2x+sqrt2
C.x^2/5+sqrt3x+1
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Answer 58

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