Question

PLS HELPLPPPLPLLLPPL
Let f(x)=1/2x^2+4.

The function g(x) is a vertical stretch of f(x) by a factor of 4.

What is the equation of g(x)?

Enter your answer in the box.

g(x) =

Answer 1

In other words, g(x) = 4f(x).

Answer 2

write it in like that? 4f(x)

Answer 3

No, you have to multiply the expression for f(x) by 4.

Answer 4

so.. what is it lol

Answer 5

You tell me ... after multiplying the expression for f(x) by 4.

Answer 6

smh.

Answer 7

What's the matter. Don't feel like doing the work?

Answer 8

pretty much x'D

Answer 9

fine do you have the answer?

Answer 10

Well, if you don't feel like doing it, then neither do I.

Answer 11

i'll do it if you're sure you know it

Answer 12

I know it.

Answer 13

okay one sec lemme solve it

Answer 14

i got x^2+32/2 ..

Answer 15

If you apply 4f(x), please show me your setup for that.

Answer 16

oml.

Answer 17

hold up i did it once more to double check and i got 2x^2+4

Answer 18

@plshelpmeoml can you please show me your setup for 4f(x)?

Answer 19

can you pls tell me if it's correct first? @Hero

Answer 20

Put it this way. If you graph both and look at the y value of the vertex for each, the value of g(x) should be 4 times that of f(x).

Answer 21

:/ yo why is this one question taking forever???!?!? jeezuz

Answer 22

hey if you ain't gon give it to me straight up then i'll ask someone else.

Answer 23

I AM helping. I just gave you the biggest hint of all.

Answer 24

i just want the answer not help

Answer 25

We don't give just answers here. If you want that, go to JustAnswers site.

Answer 26

aha funny.

Answer 27

Maybe this will help, but next time, be more willing to participate because I'm not going to help you like this anymore. https://www.desmos.com/calculator/tenqf4aien

Answer 28

so it's 2x^2+16

Answer 29

@Hero

Answer 30

Yes

Answer 31

ok thanks

Answer 32

By the way, check out this: You can actually type 4f(x) and it superimposes over g(x) to confirm the same graph: https://www.desmos.com/calculator/xtgxiz7bm3