Question

Completely factor the polynomial below.
8q^2+6q-5
A. (4q-1)(2q+5)
B. (4q+1)(2q-5)
C. (4q-5)(2q+1)
D. (4q+5)(2q-1)

Answer 1

@Mal87 let's see your steps for this.

Answer 2

We have,

=> 8q² + 6q - 5 = 0

By middle term splitting method

=> 40 = 4 x 10

Thus

=> 8q² + 10q - 4q - 5 = 0

=> 2q(4q + 5) - (4q + 5) = 0

=> (D) (4q + 5)(2q - 1)

Answer 3

@Hero

Answer 4

That's the best response I've seen all day. Looks like you figured it out quicker than I thought you would. At least I think you did. Can't look over your shoulder. I notice though you like skipping steps. Just to make sure you have it see if you can factor
\(5x^2 + 23x + 12\)