Question

A

Answer 1

@Vocaloid

Answer 2

(A) would be refraction not reflection, reflection is when it bounces across the surface

Answer 3

C

Answer 4

good

Answer 5

C

Answer 6

hm

if I understand correctly, n1 and sin1 are 35 degrees and 1.5 right

so theta2 would be arcsin(1.5sin(35)/1) = ?

Answer 7

try this

http://www.wolframalpha.com/input/?i=arcsin(1.5sin(35))

Answer 8

B

Answer 9

when I plugged it into my calculator I end up with 59.36 degrees making A the better option

Answer 10

Okay I will go with what you say =)

Answer 11

the arcsin needs to be at the beginning

Answer 12

ohhh okay that is my mistake

Answer 13

arcsin(1.5sin(35))

Answer 14

A

Answer 15

good

Answer 16

D

Answer 17

plane mirrors typically create (virtual) images, which is probably what they're looking for here

Answer 18

Choice D

Answer 19

so choice a

Answer 20

yeah (I'm just going off of what I found on the internet so I'm not 100% sure but that seems like the best option)

Answer 21

A

Answer 22

mirrors reflect not refract

Answer 23

OH i got them swtiched

Answer 24

B

Answer 25

yeah so B

Answer 26

And this one im not sure, maybe D

Answer 27

the refracting object has curves on both sides so it is probably a convex mirror not a lens

in this case, the image is real and larger judging by position and size

making A the best option