Question

A seal dove 95 meters below the surface of the water to reach a fish. It traveled 18% of the total distance every second.

What was the depth of the seal after 5 seconds?

–17.1 meters
–34.2 meters
–85.5 meters
–68.4 meters

Answer 1

What do u think?

Answer 2

Ik z answer

Answer 3

They want us to find the seals depth after 5 seconds.
First you want to find 18% of 95 (since we knows the seal travels 18% of the total distance of 95, every second).

\[95m \times 0.18 = 17.1m/s\]
Next, we multiply the rate of 17.1m per second by 5 seconds, in order to get his distance traveled after 5 seconds at that rate.
\[\frac{ 17.1m }{ s } \times 5s = 85.5m\]
Since they set y = 0 at the surface of the water, traveling downward would mean the values are negative, that means that it would be
\[-85.5m\]