Question

If 56 C flows past a point in 10.0 A of current, then how much time elapsed?

2.0 s
11.2 s
5.6 s
20.0 s

Answer 1

@Shadow
56/10=5.6, so C?

Answer 2

\(Q=IT\)
where
\(Q=charge\)

Answer 3

\ \[\Delta t = \frac{ \Delta Q }{ I }\]

Answer 4

Change in time = charge/ the current

Answer 5

So I was right...?

Answer 6

yes