Question

https://gyazo.com/00e133b155301d8859d173ba1409f829

So I did the dot product and I got: (2,-10,-1)
Then I did:
A=√((2)^2+(-10)^2+(-1)^2)
I got:
A = √105
Am I correct?

Answer 1

you mean cross product?

Answer 2

\[<3,2,-2>\times<2,-1,2>\]

\[\begin{array}{ccccc}
i&j&k&i&j\\
3&2&-2&3&2\\
2&-1&2&2&-1
\end{array}\]

\[=(2\cdot 2-(-2)(-1))\vec{i}+(-2\cdot 2-3\cdot2)\vec{j}+(3(-1)-2\cdot 2)\vec{k}\]

\[=2\vec{i}-10\vec{j}-7\vec{k}=<2,-10,-7>\]