Question

f(x)=x^2-x-12/x-2

Answer 1

Is the equation \(f(x)=\large \frac{x^2-x-12}{x-2}\)

Answer 2

yes

Answer 3

What is the question? Divide?

Answer 4

find the zeros of each function

Answer 5

@Aeon

Answer 6

We are asked to find the zeros of the function: \[\large{f(x)=\frac{x^2-x-12}{x-2}}\]Step one: you cannot have the denominator as zero, so \(x-2\ne0\)\[\therefore x\cancel{-2\color{red}{+2}}\ne0\color{red}{+2}\]\[x\ne2\]This is your asymptote (a spot in the graph where the function does not enter)

Answer 7

dont need anymore!!!

Answer 8

You can still check your question result with this. :)

Answer 9

( ͡° ͜ʖ ͡°)