D?
I got something a little different wavelength = v/f = (3*10^8)/(5*10^14) = ?
A
perfect
|dw:1526568066881:dw| kinda just have to know this ^_^
D
shorter wavelengths = higher energy microwaves are much lower energy than visible light so microwaves have longer wavelengths as a good memory device: infra means below in Latin and ultra means above, so ultraviolet means above violet, or above the visible light spectrum making UV the best answer
|dw:1526571444682:dw| lenses refract, mirrors reflect
C?
good
here are the charts that have to do with this
trying to teach myself this but since the mirror curves outward, is it convex or concave?
the mirror in your problem goes the other way so its convex to distinguish between real and virtual, do the rays of light converge?
A convex lens, also known as a positive lens, is described as having thin edges and a thick middle surface. When rays of light pass through this lens the refracted rays of light, converge at one single point which is called a principal or focal point. Read more: Difference between Real Image and Virtual Image | Difference Between http://www.differencebetween.net/technology/difference-between-real-image-and-virtual-image/#ixzz5Fm63EP9w
A real image is defined as one that is formed when rays of light are directed in a fixed point. Read more: Difference between Real Image and Virtual Image | Difference Between http://www.differencebetween.net/technology/difference-between-real-image-and-virtual-image/#ixzz5Fm68VOYd
ok, but take a look at your problem - the solid line represents where the rays of light actually are, do the solid lines converge?
oh sorry i didnt know what you ere asking Yes they do
|dw:1526572442635:dw|
notice how the bottom ray bounces off the mirror and doesn't intersect the first ray so they don't converge, producing a virtual image so convex mirror + virtual image
|dw:1526572773751:dw|
its either d or c
D?
uh I really wouldn't know this one, if you plug in do = 50 and f = 25 you get D your chart says focal length is negative for a convex mirror though so plugging in do = 50 and f = -25 gives (50)(-25)/ (50+25)
well that would give me 16.3
should i just go with either c or d
my search says that focal length is negative and the image is behind the mirror so it has to be A
B
good
A
troughs and crests are for transverse waves when the waves are ~compressed~ is this a compression or a rarefaction?
compression
good so compression = your sol'n
A
|dw:1526576054424:dw|
remember, if an object is [color] it has to absorb every color of light except [color]
so blue
good
C
good
x rays??
or maybe visivle light
unsure on thsi one
unsure on thsi one
unsure on thsi one
unsure on thsi one
unsure on thsi one
well done (x-rays not visible)
A
|dw:1526576329370:dw|
sound waves are mechanical and longitudinal which leads us towards answer choice..?
D
perfect
B
|dw:1526576467387:dw| sound is proportional to 1/r^2 making the factor..?
1/9
good so which answer choice might this correspond to?
A
good
A
|dw:1526576620292:dw| they're not perpendicular but there's another property that they share
C
good
C
not quite, changing the wavelength won't slow it down remember that energy + wavelength are inversely related
so energy will increase
D
*inversely* related means that if one goes up the other goes down wavelength goes up --> energy goes down (decreases)
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