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4p^2/4p^3
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I dont know how this thing works but the answer is p^5
The answer should be a fraction..
\[\frac{ 4p^2 }{ 4p^3 } = \frac{ p^2 }{ p^3 } = \frac{ 1 }{ p^{3 -2} } = \frac{ 1 }{ p }\]
@Allison Does that make sense to you?
Yes sir
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How did you get the 3-2?
\[\frac{ x^a }{ x^b }= \frac{ 1 }{ x^{b-a} }\]
Huh
Subtract the bottom exponent by the top exponent
Why is the one just hanging there
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\[\frac{ p }{ p } =1\]
Oh
\[\frac{ 4p^2 }{ 4p^2 } \times \frac{ 1 }{ p } = 1 \times \frac{ 1 }{ p }\]
Thank you
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