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Geometry question, please help!
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@hardlyhuman how far have you gotten with attempting to solve this problem?
not at all
Are you familiar with trig ratios for this?
not really
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|dw:1526678752552:dw|
\(\sin(\theta) = \dfrac{a}{c}\) \(\cos(\theta) = \dfrac{b}{c}\) \(\tan(\theta) = \dfrac{a}{b}\)
@hardlyhuman that's your clue.
okay thanks
Are you going to try calculating? If so, then which trig ratio are you going to use?
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sin
Great. Let me know what you get for your result.
B
Can you show the work you did to arrive at B as your correct result?
Short leg is half the hypotenuse is 6 so x = long leg so x= short leg times √3
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