Graphing help
@dude
get graphite pencils
Leave him omg
Don’t tag Dude e.e
What's the question?
Kys
It’s just checking e.e
\(\checkmark\) Okay, post ahead
Do you see de doot?
Okay, do you have any idea on how to graph this? Yes I see the point
Yeah is it that? o.e
bro get the graphite pencils
Derick don’t distract shhh
I mean its a start but the graph is incomplete, they equation they gave you is the equation of a line \(y=mx+b\) But we don't see any x in there so it must be 0 \(y=0x+5\\ y=5\) If the slope is 0 do you know how a lint must look like?
A what? Lint?
Line*
Oh
\(y = 5\) is equivalent to the point \((x,5)\) where x represents all real values from \(-\infty, \infty\)
Hero I dont think she knows domain and range yet
Unless you understood that Allison
No, no your point was right, y=5 is where you originally placed it
No need to post that twice.
i know that stuffs
Is it in pre-algebra? o.o
i learned it now in Alg 1
|dw:1526680113871:dw| This was right but the graph is supposed to look like a line
I made it a line o.o all the way??
Yes
Oh
Alrighty
Thank you c:
|dw:1526680264391:dw| That is right Algebraically you can view it as \(y=0x+5\) If you substitute any number in for x, it will always be 5 Ex. 1 \(\bf If~x~is~7\) \(y=(0\times 7)+5\\ y=0+5\) Ex 2. \(\bf If~x~is~-4\) \(y=0x+5\\ y=(0\times -4)+5\\ y=0+5\\ y=5\) It will always be 5
All the way okai
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