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Math Question https://imgur.com/btLtoiJ
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LMAO
Stop it Hero.
LMAO HE EDITED THE PROBLEM
\[\frac{ 4a^3 b^3 }{ 2ba^2 }\] \[\frac{ 4 }{ 2 } = 2\] \[\frac{ a^3 }{ a^2} = a^{3 - 2} = a\] \[\frac{ b^3 }{ b } = b^{3-1} = b^{2}\]
Medal me guys I gave him the answer
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Clearly
I know <3
I'm a smart fellow.
Please write my name in credits. Thank you.
LOL
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