Given: Triangles ABC and DBC are isosceles, m∠BDC = 30°, and m∠ABD = 155°.

Find m∠ABC, m∠BAC, and m∠DBC.

Question

Given: Triangles ABC and DBC are isosceles, m∠BDC = 30°, and m∠ABD = 155°.

Find m∠ABC, m∠BAC, and m∠DBC.

slipknot3066 · Answer

https://www.usatestprep.com/modules/gallery/files/76/7656/7656.jpg

Razor · Answer

What a weird triangle..
Okay 
Since the triangle DBC is isosceles, angles ∠BCD and ∠CDB are equal. 
∠CDB=30° ⇒ ∠BCD=30°. The sum of all angles in the triangle is 180°.
∠DBC=180°-30°-30°=120°.

Razor · Answer

∠ABC=155°-120°=35°. Triangle ABC is also isosceles, so two angles that lie on the base are equal, too 
∠BAC=∠ABC=35°

Razor · Answer

Understand?

slipknot3066 · Answer

yes

Razor · Answer

Good! GL