?
uh not really sure what 14 is asking but 13 and 15 are just the same two formulas from before
could you just post that chart one more time
so I can refer back to that
|dw:1527826815014:dw|
pi/5+7pi/6=41pi/30(New Theta)
good, now find r1r2
2-8=16?
2*8**
good
so 16[cos(41pi/30)]+isin [(41pi/30)]
good, then for 15 repeat with the division formula make sure to get the order right, it's z1/z2
0.25[cos(-29pi/30)]+isin [(-29pi/30)]
good for practical purposes it would be a good idea to re-define theta so it's positive so you just need to add 2pi to -29pi/30 to get 31pi/30
not really sure what convention your book/teacher prefers
Yeah I think I got it so you dont know what 14 would be :S
oh yeah for 14 the horizontal line just means the conjugate of z2
so just change the + sign to a - sign and copy the rest over
so -8and the rest stays the same
the + sign in the middle, not in front
oh in fron of Isin
so 8(cos(7pi/6)-i sin(7pi/6))
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