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Mathematics 12 Online
zarkam21:

4 part question

zarkam21:

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zarkam21:

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Vocaloid:

|dw:1527914039165:dw| judging by the equation what kind of shape do you think the graph might have?

zarkam21:

cardioid

Vocaloid:

good then for part II you just need to plug in theta into r = 2 + 2sin(theta) to get the appropriate r value for each row

zarkam21:

2 4 2 0 2

Vocaloid:

good then for part III you just need to graph these points

zarkam21:

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Vocaloid:

hm. not sure why there's a point all the way out at 6 notice how you got 2 when you plugged in theta = 0

zarkam21:

yes

Vocaloid:

you plotted 6 at theta = 0

zarkam21:

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zarkam21:

like that

Vocaloid:

good then you just need to connect the points w/ the cardioid shape

Vocaloid:

|dw:1527914892953:dw|

Vocaloid:

|dw:1527914924411:dw|

Vocaloid:

something like that

zarkam21:

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Vocaloid:

awesome then for part IV you just need to identify what's symmetric (as a hint there's only one type of symmetry here)

zarkam21:

the ones on the 0 line

Vocaloid:

|dw:1527915067768:dw|

Vocaloid:

be careful, it's the y-axis not the x-axis that makes this graph symmetric

zarkam21:

so the point in the middle?

Vocaloid:

|dw:1527915147342:dw|

Vocaloid:

this line, not just the point

zarkam21:

3pi/2 and pi/2?

Vocaloid:

good, so we would say this is symmetric about the vertical axis

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