4 part question
|dw:1527914039165:dw| judging by the equation what kind of shape do you think the graph might have?
cardioid
good then for part II you just need to plug in theta into r = 2 + 2sin(theta) to get the appropriate r value for each row
2 4 2 0 2
good then for part III you just need to graph these points
hm. not sure why there's a point all the way out at 6 notice how you got 2 when you plugged in theta = 0
yes
you plotted 6 at theta = 0
like that
good then you just need to connect the points w/ the cardioid shape
|dw:1527914892953:dw|
|dw:1527914924411:dw|
something like that
awesome then for part IV you just need to identify what's symmetric (as a hint there's only one type of symmetry here)
the ones on the 0 line
|dw:1527915067768:dw|
be careful, it's the y-axis not the x-axis that makes this graph symmetric
so the point in the middle?
|dw:1527915147342:dw|
this line, not just the point
3pi/2 and pi/2?
good, so we would say this is symmetric about the vertical axis
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