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Mathematics 11 Online
zarkam21:

rose?

zarkam21:

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zarkam21:

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zarkam21:

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zarkam21:

r=4cos(4(0))=4 r=4cos(4(pi/2))=4 r=4cos(4(pi))=4 r=4cos(4(3pi/2))=6pi r=4cos(4(2pi))=4

zarkam21:

and then rose for part I

Vocaloid:

r=4cos(4(3pi/2))= 4 not 6pi (so every value in the table is 4) then you just need to plot/sketch, etc.

zarkam21:

im having trouble with (4,2pi

zarkam21:

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zarkam21:

oh nvm

zarkam21:

here is the final

Vocaloid:

good then you just need to sketch something like |dw:1527915919330:dw|

Vocaloid:

|dw:1527915925607:dw|

Vocaloid:

just a little neater, make sure all the petals stop at 4

zarkam21:

okay got it now prt IV

Vocaloid:

if you notice, every pi/4 units there's a line of symmetry, so you would list out all the intervals of pi/4 starting from 0 there's also radial symmetry since every corresponding point is equidistant from the origin

zarkam21:

0,pi,pi/2?

zarkam21:

like that

zarkam21:

3pi/2

Vocaloid:

actually come to think of it you can stop at pi

zarkam21:

2pi

Vocaloid:

so 0, pi/4, pi/2, then 3pi/4 the line through 0 already includes pi

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