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f(x)=log(x+3) inverse?
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replace f(x) with y y = log(x+3) switch x and y to get x = log(y+3) ^ try solving this equation for y, that will give you the inverse function
how will i solve the equation for y ?
so you have log(y+3) on the right side, to "undo" a logarithm, raise both sides to the base of 10 so you get 10^x = y + 3, then you just need to subtract 3 from both sides to get y
7^x=y is what i got
10^x and 3 are not like terms so you cannot subtract them to get 7^x 10^x = y + 3 subtracting 3 from both sides gives us y = 10^x - 3 as your inverse
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using the original notation \(f^{-1}(x)\)= 10^x - 3
yes i was about to say that ! thanks again.
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